JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumMulti-step
JEE Main 28 July 2022, Shift 2, Physics Q10
Question 10 of 90 in this shift, Physics question 10 of 30, Section A.
A uniform electric field E = (8m/e) V/m is created between two parallel plates of length 1 m as shown in figure. (where m = mass of electron and e = charge of electron). An electron enters the field symmetrically between the plates with a speed of 2 m/s. The angle of the deviation () of the path of the electron as it comes out of the field will be ________.
The figure, in words
Two horizontal parallel plates of length 1 m (upper plate marked with + signs, lower plate with - dashes); electric field E points downward; electron enters at the middle with speed 2 m/s and leaves along a curved path bending upward, with deviation angle theta measured from the horizontal.- (1)
- (2)Official answer
- (3)
- (4)
Official answer
Option 2
NTA final key.
- Chapter
- Electric Charges and Fields
- Topic
- Electric Field
- Idea tested
- Charged Particle Trajectory in E-Field