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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 27 July 2022, Shift 1, Physics Q37

Question 37 of 90 in this shift, Physics question 7 of 30, Section A.

If K1K_1 and K2K_2 are the thermal conductivities, L1L_1 and L2L_2 are the lengths and A1A_1 and A2A_2 are the cross sectional areas of steel and copper rods respectively such that K2K1=9\frac{K_2}{K_1}=9 , A1A2=2\frac{A_1}{A_2}=2, L1L2=2\frac{L_1}{L_2}=2. Then, for the arrangement as shown in the figure, the value of temperature T of the steel - copper junction in the steady state will be :

The figure, in words

A steel rod and a copper rod joined end to end in a line; the steel end is at the left labelled 'Furnace 450°C', the copper end at the right labelled 'Ice box 0°C'; the junction is marked with temperature T; 'Insulating material' is labelled below the rods, which are surrounded by it.
  1. (1)18°C
  2. (2)14°C
  3. (3)45°COfficial answer
  4. (4)150°C

Official answer

Option 3

NTA final key.