JEE Main 2022 · PhysicsMultiple choiceDiagram basedMediumMulti-step
JEE Main 26 July 2022, Shift 1, Physics Q40
Question 40 of 90 in this shift, Physics question 10 of 30, Section A.
The current I in the given circuit will be :
The figure, in words
Rectangular circuit with a 40 V cell (+ on the left, - on the right) in the bottom wire and current arrow I pointing up on the left wire. Along the upper main wire, from left to right, are a 4 ohm resistor, a 2 ohm resistor and a 4 ohm resistor. A further 4 ohm resistor is drawn on a bypass wire above, joining the point before the first 4 ohm resistor to the point between the 2 ohm and the right-hand 4 ohm resistors. Another 4 ohm resistor is drawn on a bypass wire below, joining the point between the first 4 ohm and the 2 ohm resistors to the right-hand end of the right-hand 4 ohm resistor.- (1)10 AOfficial answer
- (2)20 A
- (3)4 A
- (4)40 A
Official answer
Option 1
NTA final key.
- Chapter
- Current Electricity
- Topic
- Kirchhoff's Laws
- Idea tested
- Balanced Wheatstone Bridge