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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 26 February 2021, Shift 2, Physics Q15

Question 15 of 90 in this shift, Physics question 15 of 30, Section A.

The length of metallic wire is l1l_1 when tension in it is T1T_1. It is l2l_2 when the tension is T2T_2. The original length of the wire will be :
  1. (1)l1+l22\frac{l_1 + l_2}{2}
  2. (2)T2l1+T1l2T1+T2\frac{T_2 l_1 + T_1 l_2}{T_1 + T_2}
  3. (3)T1l1−T2l2T2−T1\frac{T_1 l_1 - T_2 l_2}{T_2 - T_1}
  4. (4)T2l1−T1l2T2−T1\frac{T_2 l_1 - T_1 l_2}{T_2 - T_1}Official answer

Official answer

Option 4

NTA final key.