JEE Main 2021 · ChemistryMultiple choiceDiagram basedMediumMulti-step
JEE Main 26 February 2021, Shift 1, Chemistry Q42
Question 42 of 90 in this shift, Chemistry question 12 of 30, Section A.
For the given reaction :
[reaction scheme, see figure_note: structure (A) (major product)]
What is ‘A’ ?
The figure, in words
Stem scheme as drawn: CH=CHBr with CH3 attached by a vertical bond below the left CH; arrow labelled 1. NaNH2, 2. Red hot iron tube, 873 K; product (A) (major product). Option 1: CH=CH-NH2 with CH3 below the first CH. Option 3: hexagon with alternating double bonds, no substituents. Option 4: hexagon with alternating double bonds (no inner circle), H3C at upper-left vertex, CH3 at upper-right vertex, CH3 at bottom vertex.- (1) with attached below the first CH
- (2)
- (3)[figure: six-membered ring drawn with alternating double bonds, no substituents]
- (4)[figure: six-membered ring drawn with alternating double bonds, bearing on the upper-left vertex, on the upper-right vertex and on the bottom vertex]Official answer
Official answer
Option 4
NTA final key.
- Chapter
- Hydrocarbons
- Topic
- Alkenes and Alkynes
- Idea tested
- Cyclic Polymerization of Alkynes