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Saturday, 31 October

JEE Main 2021 · ChemistryMultiple choiceDiagram basedMediumMulti-step

JEE Main 25 February 2021, Shift 1, Chemistry Q44

Question 44 of 90 in this shift, Chemistry question 14 of 30, Section A.

Identify A and B in the chemical reaction.

The figure, in words

Reactant: six-membered ring with one double bond (on the right side), OCH3\mathrm{OCH_3} at the top vertex and NO2\mathrm{NO_2} at the bottom vertex. Arrow labelled HCl gives [A] (major); arrow labelled NaI, dry acetone gives [B] (major). In every option the rings of A and B are drawn with single bonds only.
  1. (1)A = ring with OCH3\mathrm{OCH_3} at top vertex, Cl at upper-right vertex, NO2\mathrm{NO_2} at bottom vertex; B = ring with I at top vertex, Cl at upper-right vertex, NO2\mathrm{NO_2} at bottom vertex
  2. (2)A = ring with OCH3\mathrm{OCH_3} at top vertex, Cl at upper-right vertex, NO2\mathrm{NO_2} at bottom vertex; B = ring with OCH3\mathrm{OCH_3} at top vertex, I at upper-right vertex, NO2\mathrm{NO_2} at bottom vertexOfficial answer
  3. (3)A = ring with OCH3\mathrm{OCH_3} at top vertex, Cl at lower-right vertex, NO2\mathrm{NO_2} at lower-left vertex; B = ring with I at top vertex, Cl at lower-right vertex, NO2\mathrm{NO_2} at lower-left vertex
  4. (4)A = ring with OCH3\mathrm{OCH_3} at top vertex, Cl at upper-right vertex, NO2\mathrm{NO_2} at bottom vertex; B = ring with OCH3\mathrm{OCH_3} at top vertex, Cl at lower-right vertex, NO2\mathrm{NO_2} at bottom vertex

Official answer

Option 2

NTA final key.

Chapter
Haloalkanes and Haloarenes
Topic
Alkenes and Alkynes
Idea tested
Markovnikov's Rule Application

Same idea in other shifts

Asked 13× in all
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  5. 31 Jan 2024, Shift 2 · Q75Major product of the following reaction is -HardDiagram basedHas a figure
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  7. 24 Jun 2022, Shift 1 · Q90The major product 'A' of the following given reaction has ______ sp2sp^2 hybridized carbon atoms. 2,7-Dimethyl-2,6-octadiene…HardNumerical value
  8. 25 Jun 2022, Shift 1 · Q73The product formed in the following reaction. [figure: (CH3)2C=CH2\mathrm{(CH_3)_2C{=}CH_2} drawn with two CH3\mathrm{CH_3} on the left carbon and…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.