JEE Main 2025 · ChemistryMultiple choiceDiagram basedHardApplication
JEE Main 4 April 2025, Shift 2, Chemistry Q65
Question 65 of 75 in this shift, Chemistry question 15 of 25, Section A.
Consider the following molecule (X).
The structure of X is [figure: tricyclic fused polycyclic hydrocarbon (X) containing a cyclopentene ring with a C=C, a six-membered ring with a C=C, and a lower five-membered ring with an exocyclic-type C=C at the ring fusion]
The major product formed when the given molecule (X) is treated with HBr (1 eq) is :
The figure, in words
Structure X: fused tricyclic hydrocarbon with three C=C bonds (one in the upper cyclopentene ring, one in the six-membered ring, one at the lower five-membered ring); options show HBr addition products.- (1)[figure: tricyclic structure with Br on the tertiary ring-fusion carbon of the lower five-membered ring; both other C=C bonds retained]Official answer
- (2)[figure: tricyclic structure with Br and H on a carbon of the six-membered ring; lower C=C and cyclopentene C=C retained]
- (3)[figure: tricyclic structure with Br and H on a CH carbon of the upper five-membered ring; six-membered ring C=C and lower C=C retained]
- (4)[figure: tricyclic structure with Br and H on a CH carbon of the lower-left five-membered ring; six-membered ring C=C and lower C=C retained]
Official answer
Option 1
NTA final key.
- Chapter
- Haloalkanes and Haloarenes
- Topic
- Alkenes and Alkynes
- Idea tested
- Markovnikov's Rule Application