Learn

Friday, 9 October

JEE Main 2025 · ChemistryMultiple choiceDiagram basedHardApplication

JEE Main 4 April 2025, Shift 2, Chemistry Q65

Question 65 of 75 in this shift, Chemistry question 15 of 25, Section A.

Consider the following molecule (X). The structure of X is [figure: tricyclic fused polycyclic hydrocarbon (X) containing a cyclopentene ring with a C=C, a six-membered ring with a C=C, and a lower five-membered ring with an exocyclic-type C=C at the ring fusion] The major product formed when the given molecule (X) is treated with HBr (1 eq) is :

The figure, in words

Structure X: fused tricyclic hydrocarbon with three C=C bonds (one in the upper cyclopentene ring, one in the six-membered ring, one at the lower five-membered ring); options show HBr addition products.
  1. (1)[figure: tricyclic structure with Br on the tertiary ring-fusion carbon of the lower five-membered ring; both other C=C bonds retained]Official answer
  2. (2)[figure: tricyclic structure with Br and H on a carbon of the six-membered ring; lower C=C and cyclopentene C=C retained]
  3. (3)[figure: tricyclic structure with Br and H on a CH carbon of the upper five-membered ring; six-membered ring C=C and lower C=C retained]
  4. (4)[figure: tricyclic structure with Br and H on a CH carbon of the lower-left five-membered ring; six-membered ring C=C and lower C=C retained]

Official answer

Option 1

NTA final key.