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JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 26 August 2021, Shift 2, Physics Q9

Question 9 of 90 in this shift, Physics question 9 of 30, Section A.

A particle of mass m is suspended from a ceiling through a string of length L. The particle moves in a horizontal circle of radius r such that

\mathrm{r}=\frac{L}{\sqrt{2}}

. The speed of particle will be :

(1) $\sqrt{rg}$ Official answer
(2) $\sqrt{\frac{rg}{2}}$
(3) $\sqrt{2rg}$
(4) $2\sqrt{rg}$

Official answer

Option 1

NTA final key.

Chapter: Laws of Motion
Topic: Circular Motion
Idea tested: Conical Pendulum Dynamics

Same idea in other shifts

Asked 2× in all

3 Aug 2021, Shift 1 · Q6As shown in the figure, a string of length ‘ $l$ ' holds a small bob of mass ‘ $m$ ' while suspended from a point `O'. The bob revolves about…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.