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Saturday, 31 October

JEE Main 2021 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 26 August 2021, Shift 2, Maths Q69

Question 69 of 90 in this shift, Maths question 9 of 30, Section A.

A 10 inches long pencil AB with mid point C and a small eraser P are placed on the horizontal top of a table such that PC=5\mathrm{PC}=\sqrt{5} inches and ∠PCB=tan⁡−1(2)\angle\mathrm{PCB}=\tan^{-1}(2). The acute angle through which the pencil must be rotated about C so that the perpendicular distance between eraser and pencil becomes exactly 1 inch is :

The figure, in words

A horizontal pencil drawn as a long cylinder with ends A (left) and B (right), midpoint C marked, each half labelled 5 in. A line segment from C to a point P above the pencil, labelled 5\sqrt{5} in.
  1. (1)tan⁡−1(43)\tan^{-1}\left(\frac{4}{3}\right)
  2. (2)tan⁡−1(34)\tan^{-1}\left(\frac{3}{4}\right)Official answer
  3. (3)tan⁡−1(1)\tan^{-1}(1)
  4. (4)tan⁡−1(12)\tan^{-1}\left(\frac{1}{2}\right)

Official answer

Option 2

NTA final key.