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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceDiagram basedMediumCalculation

JEE Main 26 August 2021, Shift 1, Physics Q18

Question 18 of 90 in this shift, Physics question 18 of 30, Section A.

The magnitude of vectors OA→\overrightarrow{OA}, OB→\overrightarrow{OB} and OC→\overrightarrow{OC} in the given figure are equal. The direction of OA→+OB→−OC→\overrightarrow{OA}+\overrightarrow{OB}-\overrightarrow{OC} with xx-axis will be :

The figure, in words

x and y axes (dotted) meeting at O. Vector OA points up and to the right, 30° above the +x axis; vector OB points down and to the right, 60° below the +x axis (angle marked 60° between +x axis and OB); vector OC points up and to the left, 45° above the −x axis.
  1. (1)tan⁡−1(1−3−2)(1+3+2)\tan^{-1}\frac{(1-\sqrt{3}-\sqrt{2})}{(1+\sqrt{3}+\sqrt{2})}Official answer
  2. (2)tan⁡−1(3−1+2)(1+3−2)\tan^{-1}\frac{(\sqrt{3}-1+\sqrt{2})}{(1+\sqrt{3}-\sqrt{2})}
  3. (3)tan⁡−1(1+3−2)(1−3−2)\tan^{-1}\frac{(1+\sqrt{3}-\sqrt{2})}{(1-\sqrt{3}-\sqrt{2})}
  4. (4)tan⁡−1(3−1+2)(1−3+2)\tan^{-1}\frac{(\sqrt{3}-1+\sqrt{2})}{(1-\sqrt{3}+\sqrt{2})}

Official answer

Option 1

NTA final key.