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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 4 September 2020, Shift 1, Physics Q3

Question 3 of 75 in this shift, Physics question 3 of 25.

Starting from the origin at time t=0, with initial velocity 5j^5\hat{j} ms−1^{-1}, a particle moves in the x−yx-y plane with a constant acceleration of (10i^+4j^)\left(10\hat{i}+4\hat{j}\right)ms−2^{-2}. At time t, its coordinates are (20 m, y0y_0 m). The values of t and y0y_0 are, respectively :
  1. (1)2 s and 24 m
  2. (2)4 s and 52 m
  3. (3)2 s and 18 mOfficial answer
  4. (4)5 s and 25 m

Official answer

Option 3

NTA final key (Sep 2020).