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Saturday, 31 October

JEE Main 2020 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 3 September 2020, Shift 1, Physics Q25

Question 25 of 75 in this shift, Physics question 25 of 25.

When a long glass capillary tube of radius 0.015 cm is dipped in a liquid, the liquid rises to a height of 15 cm within it. If the contact angle between the liquid and glass to close to 0°, the surface tension of the liquid, in milliNewton m−1^{-1}, is [ρ(liquid)\rho_{(\mathrm{liquid})} = 900 kgm−3^{-3}, g = 10 ms−2^{-2}] (Give answer in closest integer) __________.

Official answer

101.00

NTA final key (Sep 2020).

Chapter
Mechanical Properties of Fluids
Topic
Surface Tension
Idea tested
Capillary Rise (Ascent Formula)

Same idea in other shifts

Asked 3× in all
  1. 29 Jan 2024, Shift 1 · Q37Given below are two statements: Statement I : If a capillary tube is immersed first in cold water and then in hot water, the height of…EasyTwo statements
  2. 2 Sep 2020, Shift 2 · Q7A capillary tube made of glass of radius 0.15 mm is dipped vertically in a beaker filled with methylene iodide (surface tension = 0.05…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.