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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 3 September 2020, Shift 1, Physics Q16

Question 16 of 75 in this shift, Physics question 16 of 25.

The magnetic field of a plane electromagnetic wave is B→=3×10−8sin⁡[200π (y+ct)] i^\overrightarrow{B} = 3 \times 10^{-8}\sin[200\pi\,(y + \mathrm{ct})]\,\hat{i} T where c = 3×\times108^8 ms−1^{-1} is the speed of light. The corresponding electric field is :
  1. (1)E→=3×10−8sin⁡[200π (y+ct)] k^\overrightarrow{E} = 3 \times 10^{-8}\sin[200\pi\,(y + \mathrm{ct})]\,\hat{k} V/m
  2. (2)E→=−9sin⁡[200π (y+ct)] k^\overrightarrow{E} = -9\sin[200\pi\,(y + \mathrm{ct})]\,\hat{k} V/mOfficial answer
  3. (3)E→=9sin⁡[200π (y+ct)] k^\overrightarrow{E} = 9\sin[200\pi\,(y + \mathrm{ct})]\,\hat{k} V/m
  4. (4)E→=−10−6sin⁡[200π (y+ct)] k^\overrightarrow{E} = -10^{-6}\sin[200\pi\,(y + \mathrm{ct})]\,\hat{k} V/m

Official answer

Option 2

NTA final key (Sep 2020).

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.