JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation
JEE Main 2 September 2020, Shift 2, Physics Q11
Question 11 of 75 in this shift, Physics question 11 of 25.
A 10 F capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is :
- (1)15 FOfficial answer
- (2)30 F
- (3)20 F
- (4)10 F
Official answer
Option 1
NTA final key (Sep 2020).
- Idea tested
- Charge Sharing and Heat Loss