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JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 January 2020, Shift 2, Maths Q66

Question 66 of 75 in this shift, Maths question 16 of 25, Section A.

If one end of a focal chord AB of the parabola

y^2=8x

is at

A\left(\frac{1}{2},-2\right)

, then the equation of the tangent to it at B is :

(1) $2x+y-24=0$
(2) $x+2y+8=0$
(3) $x-2y+8=0$ Official answer
(4) $2x-y-24=0$

Official answer

Option 3

NTA final key (Jan 2020).

Chapter: Conic Sections
Topic: Parabola Focal Chords
Idea tested: Parameter relation t1*t2 = -1

Same idea in other shifts

Asked 2× in all

5 Apr 2026, Shift 2 · Q12Let the directrix of the parabola $P: y^2=8x$ , cut x-axis at the point A. Let $B(\alpha, \beta)$ , $\alpha>1$ , be a point on P such that…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.