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Friday, 9 October

JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 January 2020, Shift 2, Maths Q65

Question 65 of 75 in this shift, Maths question 15 of 25, Section A.

The length of the minor axis (along yy-axis) of an ellipse in the standard form is 43\frac{4}{\sqrt3}. If this ellipse touches the line, x+6y=8x+6y=8; then its eccentricity is :
  1. (1)13113\frac{1}{3}\sqrt{\frac{11}{3}}
  2. (2)12113\frac{1}{2}\sqrt{\frac{11}{3}}Official answer
  3. (3)56\sqrt{\frac{5}{6}}
  4. (4)1253\frac{1}{2}\sqrt{\frac{5}{3}}

Official answer

Option 2

NTA final key (Jan 2020).

Chapter
Conic Sections
Topic
Ellipse Eccentricity
Idea tested
Eccentricity calculation

Same idea in other shifts

Asked 3× in all
  1. 5 Apr 2026, Shift 1 · Q9Let a focus of the ellipse E:x2a2+y2b2=1E: \frac{x^2}{a^2}+\frac{y^2}{b^2}=1 be S(4,0)S(4, 0) and its eccentricity be 45\frac{4}{5}. If the point…EasySingle correct
  2. 25 Jul 2021, Shift 1 · Q61Let an ellipse E:x2a2+y2b2=1E:\frac{x^2}{a^2}+\frac{y^2}{b^2}=1, a2>b2a^2>b^2, passes through (32,1)\left(\sqrt{\frac{3}{2}},1\right) and has eccentricity…HardSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.