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Friday, 9 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctHardMulti-step

JEE Main 8 January 2020, Shift 1, Physics Q6

Question 6 of 75 in this shift, Physics question 6 of 25, Section A.

Consider a solid sphere of radius R and mass density ρ(r)=ρ0(1−r2R2)\rho(r) = \rho_0\left(1-\frac{r^2}{R^2}\right), 0<r≤R0 < r \le R. The minimum density of a liquid in which it will float is :
  1. (1)ρ05\frac{\rho_0}{5}
  2. (2)ρ03\frac{\rho_0}{3}
  3. (3)2ρ05\frac{2\rho_0}{5}Official answer
  4. (4)2ρ03\frac{2\rho_0}{3}

Official answer

Option 3

NTA final key (Jan 2020).