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Friday, 9 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumData or graph

JEE Main 8 January 2020, Shift 1, Physics Q5

Question 5 of 75 in this shift, Physics question 5 of 25, Section A.

Consider two solid spheres of radii R1=1R_1 = 1 m, R2=2R_2 = 2 m and masses M1M_1 and M2M_2, respectively. The gravitational field due to sphere (1) and (2) are shown. The value of M1M2\frac{M_1}{M_2} is :

The figure, in words

Graph of gravitational field E (vertical, 1-4) vs radius R (horizontal, 0-5). Curve (1) rises linearly to peak E=2 at R=1 then decays; curve (2) rises linearly to peak E=3 at R=2 then decays.
  1. (1)16\frac{1}{6}Official answer
  2. (2)13\frac{1}{3}
  3. (3)12\frac{1}{2}
  4. (4)23\frac{2}{3}

Official answer

Option 1

NTA final key (Jan 2020).

Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.