Lesson 4 of 10 · 7 min
Resolving vectors into components
NCERT §3.5
Meera fields the ball at the boundary and throws it to the keeper at 20 m/s, 30° above the ground. How much of that 20 m/s carries the ball towards the keeper, and how much lifts it?
The lesson in notes
In short
Any vector A in a plane can be written as λa + μb along two chosen non-parallel vectors a and b; λa and μb are its components along them.
Unit vectors î, ĵ, k̂ have magnitude 1, point along +x, +y and +z, and have no dimension or unit. Any vector A equals |A| n̂, where n̂ is the unit vector along A.
A vector of magnitude A at angle θ to the x-axis has components Ax = A cos θ and Ay = A sin θ, so A = Ax î + Ay ĵ. A component can be positive, negative or zero.
From the components back to the vector: A = √(Ax² + Ay²) and tan θ = Ay/Ax. A ball thrown at 20 m/s at 30° has components 17.3 m/s and 10.0 m/s.
In three dimensions, Ax = A cos α, Ay = A cos β, Az = A cos γ, where α, β, γ are the angles with the axes, and A = √(Ax² + Ay² + Az²).
The position vector of a point (x, y, z) is r = x î + y ĵ + z k̂.
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Magnitude and direction from components
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