Lesson 5 of 9 · 6 min
Shear modulus
NCERT §8.5.2
A heavy compressor on the site sits on a lead slab 50 cm square and 10 cm thick, riveted to the floor along its lower edge. When the machine jerks sideways, the slab's top edge is pushed with 9.0 × 10⁴ N. How far does it move?
The lesson in notes
In short
Shear modulus (modulus of rigidity) G = shearing stress σs ÷ shearing strain = (F/A)/(Δx/L) = FL/(AΔx).
Because shearing strain ≈ θ, G = (F/A)/θ = F/(Aθ), and so σs = Gθ.
G is in N m⁻² or Pa. It is generally smaller than Young's modulus; for most materials G ≈ Y/3.
Typical G values: tungsten has the stiffest at 150 GPa, steel 84, nickel 77 and iron 70; copper 42, brass 36, aluminium 25 and glass 23; wood 10 and lead only 5.6 GPa.
Lead slab 50 cm square and 10 cm thick, lower edge riveted to the floor, sheared by 9.0 × 10⁴ N on its narrow face: A = 0.5 m × 0.1 m = 0.05 m², stress = 1.8 × 10⁶ N m⁻², and with G = 5.6 × 10⁹ N m⁻² the upper edge moves Δx = stress × L/G = 1.6 × 10⁻⁴ m = 0.16 mm.
Shear, like stretching, needs a body with a definite shape, so Young's modulus and shear modulus apply only to solids.
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Shear stress, strain and modulus
Khan Academy India - English · English · Lecture · Open on YouTube