Lesson 11 of 12 · 8 min
Identities JEE adds
NCERT §2.3
Measure the cabin's angle up from the hub's level, then its angle from the upward vertical through the hub. The two always add to a right angle. That is sin⁻¹ x + cos⁻¹ x = π/2 in wheel form.
The lesson in notes
In short
The rationalised textbook proves only the undoing rules, but JEE questions use the standard identities below. Each follows from the principal ranges.
Negative inputs: sin⁻¹(−x) = −sin⁻¹ x, tan⁻¹(−x) = −tan⁻¹ x, cosec⁻¹(−x) = −cosec⁻¹ x; while cos⁻¹(−x) = π − cos⁻¹ x, cot⁻¹(−x) = π − cot⁻¹ x, sec⁻¹(−x) = π − sec⁻¹ x.
Complementary pairs: sin⁻¹ x + cos⁻¹ x = π/2 for x ∈ [−1, 1]; tan⁻¹ x + cot⁻¹ x = π/2 for all real x; sec⁻¹ x + cosec⁻¹ x = π/2 for |x| ≥ 1.
Why the first holds: if sin⁻¹ x = θ, then cos(π/2 − θ) = sin θ = x and π/2 − θ lies in [0, π], so cos⁻¹ x = π/2 − θ.
Reciprocals: cosec⁻¹ x = sin⁻¹(1/x) and sec⁻¹ x = cos⁻¹(1/x) for |x| ≥ 1; cot⁻¹ x = tan⁻¹(1/x) for x > 0 only. For x < 0, cot⁻¹ x = π + tan⁻¹(1/x).
Addition: tan⁻¹ x + tan⁻¹ y = tan⁻¹((x + y)/(1 − xy)) when xy < 1. Example: tan⁻¹(1/2) + tan⁻¹(1/3) = tan⁻¹((5/6)/(5/6)) = tan⁻¹ 1 = π/4.
Doubling: 2 tan⁻¹ x = tan⁻¹(2x/(1 − x²)) for |x| < 1, and 2 tan⁻¹ x = sin⁻¹(2x/(1 + x²)) for |x| ≤ 1.