Inverse Trigonometric Functions

Maths · Class 12

Lesson 5 of 12 · 7 min

cosec⁻¹ and sec⁻¹

NCERT §2.2

A guy rope runs from the top of a tent pole to a peg in the ground. The rope is always longer than the pole, so rope ÷ pole is at least 1, and that ratio is a secant.

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cosec x = 1/sin x is defined for x ≠ nπ and its values satisfy |y| ≥ 1, so its range is R − (−1, 1). On [−π/2, π/2] − {0} it is one-one and onto that range.

So cosec⁻¹ : R − (−1, 1) → [−π/2, π/2] − {0}. The angle 0 is removed because cosec 0 does not exist.

sec x = 1/cos x is defined for x ≠ (2n + 1)π/2, with range R − (−1, 1). On [0, π] − {π/2} it is one-one and onto that range.

So sec⁻¹ : R − (−1, 1) → [0, π] − {π/2}. The angle π/2 is removed because sec π/2 does not exist.

Both inverses reject inputs strictly between −1 and 1: cosec⁻¹(1/2) and sec⁻¹ 0 are undefined.

They follow the pattern of their partners: cosec⁻¹ 2 = π/6 and cosec⁻¹(−√2) = −π/4, as for sin⁻¹; sec⁻¹ 2 = π/3 and sec⁻¹(−2) = 2π/3, as for cos⁻¹.

Taking reciprocals converts one to the other: cosec⁻¹ x = sin⁻¹(1/x) and sec⁻¹ x = cos⁻¹(1/x) for |x| ≥ 1.

cosec⁻¹ and sec⁻¹ | Inverse Trigonometric Functions | Lumi Learn