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Friday, 9 October

JEE Main Maths · Application of Derivatives

Monotonicity in JEE Main

Monotonicity (Maths, Application of Derivatives) came 6 times in 6 of the 42 JEE Main shifts Lumi analysed, across 4 distinct ideas. 2 of them came in 2024–26; it was last asked in 2025.

Questions
6
in 6 shifts
Ideas asked
4
1 asked more than once
Numerical answer
0
0% of its questions
Pattern
Asked most years
last asked 2025
Questions each year
0240’170’202’211’221’231’241’250’26

In the shifts Lumi analysed for each year.

Difficulty and format
Easy 1Medium 3Hard 2

Format

  • Single correct4 Q
  • Two statements2 Q
Ideas inside the topic
4 ideas
Where it sits

Part of Application of Derivatives, which had 47 questions in all. Monotonicity accounts for 13% of them. In Lumi's JEE taxonomy it belongs to Calculus.

Every question

All 6 Monotonicity questions

Newest first, each with its options and official answer.

  1. 8 Apr 2025, Shift 2 · Q17Let the function f(x)=x3+3x+3f(x) = \frac{x}{3} + \frac{3}{x} + 3, x≠0x \neq 0 be strictly increasing in…EasySingle correct
  2. 8 Apr 2024, Shift 1 · Q7For the function f(x)=(cos⁡x)−x+1f(x)=(\cos x)-x+1, x∈Rx\in\mathbb{R}, between the following two statements (S1) f(x)=0f(x)=0 for only one value of xx in…MediumTwo statements
  3. 11 Apr 2023, Shift 1 · Q10Let f:[2,4]→Rf : [2, 4] \to \mathbb{R} be a differentiable function such that (xlog⁡ex)f′(x)+(log⁡ex)f(x)+f(x)≥1, x∈[2,4](x \log_e x) f'(x) + (\log_e x) f(x) + f(x) \ge 1,\ x \in [2, 4]…HardTwo statements
  4. 24 Jun 2022, Shift 1 · Q10For the function f(x)=4log⁡e(x−1)−2x2+4x+5, x>1f(x)=4\log_e(x-1)-2x^2+4x+5,\ x>1, which one of the following is NOT correct ?HardSingle correct
  5. 25 Jul 2021, Shift 1 · Q67Let f(x)=3sin⁡4x+10sin⁡3x+6sin⁡2x−3f(x)=3\sin^4x+10\sin^3x+6\sin^2x-3, x∈[−π6,π2]x\in\left[-\frac{\pi}{6},\frac{\pi}{2}\right]. Then, ff is :MediumSingle correct
  6. 16 Mar 2021, Shift 2 · Q64Let ff be a real valued function, defined on R−{−1,1}\mathbf R-\{-1,1\} and given by f(x)=3log⁡e∣x−1x+1∣−2x−1f(x)=3\log_e\left|\frac{x-1}{x+1}\right|-\frac{2}{x-1}.…MediumSingle correct