JEE Main Maths · Vector Algebra

Solving Vector Equations with Cross Products

Solving Vector Equations with Cross Products (Vector Algebra) was asked 8 times in 8 JEE Main shifts, 2021–2026, out of the 42 shifts Lumi analysed. 2 of the 8 had a numerical answer.

Times asked: 8; in 8 shifts
Years: 2021–2026
Usual format: Single correct; Multi-step
Pattern: Frequent; repeats across shifts

How it is asked

Unknown vector from cross and dot conditions
Solve vector cross product equation

Difficulty

Easy 0Medium 4Hard 4

Where it sits

Chapter: Vector Algebra. Topic: Cross Product, 32 questions over 11 ideas.

All 8 questions

Newest first, each with its options and official answer.

5 Apr 2026, Shift 1 · Q14Let $\vec{a} = \sqrt{7}\hat{i} + \hat{j} - \hat{k}$ and $\vec{b} = \hat{j} + 2\hat{k}$ . If $\vec{r}$ is a vector such that…MediumSingle correct
6 Apr 2026, Shift 1 · Q23If $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ , $\vec{b}=\hat{j}-\hat{k}$ and $\vec{c}$ be three vectors such that $\vec{a}\times\vec{c}=\vec{b}$ …MediumNumerical value
8 Apr 2026, Shift 2 · Q14Let $\vec{a} = 4\hat{i} - \hat{j} + 3\hat{k}$ , $\vec{b} = 10\hat{i} + 2\hat{j} - \hat{k}$ and a vector $\vec{c}$ be such that…MediumSingle correct
9 Apr 2024, Shift 2 · Q17Between the following two statements: Statement I : Let $\vec{a}=\hat{i}+2\hat{j}-3\hat{k}$ and $\vec{b}=2\hat{i}+\hat{j}-\hat{k}$ . Then…HardTwo statements
31 Jan 2024, Shift 1 · Q18Let $\vec{a}=3\hat{i}+\hat{j}-2\hat{k}$ , $\vec{b}=4\hat{i}+\hat{j}+7\hat{k}$ and $\vec{c}=\hat{i}-3\hat{j}+4\hat{k}$ be three vectors. If…MediumSingle correct
31 Jan 2024, Shift 2 · Q30Let $\vec{a}=3\hat{i}+2\hat{j}+\hat{k}$ , $\vec{b}=2\hat{i}-\hat{j}+3\hat{k}$ and $\vec{c}$ be a vector such that…HardNumerical value
24 Jun 2022, Shift 1 · Q16Let $\hat{a}, \hat{b}$ be unit vectors. If $\vec{c}$ be a vector such that the angle between $\hat{a}$ and $\vec{c}$ is $\frac{\pi}{12}$ ,…HardSingle correct
16 Mar 2021, Shift 2 · Q63Let $\vec a=\hat i+2\hat j-3\hat k$ and $\vec b=2\hat i-3\hat j+5\hat k$ . If $\vec r\times\vec a=\vec b\times\vec r$ ,…HardSingle correct