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Friday, 9 October

JEE Main Maths · Complex Numbers and Quadratic Equations

Root-Coefficient Relation

Root-Coefficient Relation (Complex Numbers and Quadratic Equations) was asked 8 times in 7 JEE Main shifts, 2020–2026, out of the 42 shifts Lumi analysed. 1 of the 8 had a numerical answer.

Times asked
8
in 7 shifts
Years
2020–2026
Usual format
Single correct
Multi-step
Pattern
Frequent
repeats across shifts

How it is asked

  • Unknown from roots of summed-product quadratic
  • Expression from root differences of quadratic

Difficulty

Easy 1Medium 6Hard 1

Every time it came

All 8 questions

Newest first, each with its options and official answer.

  1. 2 Apr 2026, Shift 1 · Q1Let α,α+2,α∈Z\alpha, \alpha+2, \alpha \in \mathbb{Z}, be the roots of the quadratic equation…HardSingle correct
  2. 5 Apr 2026, Shift 1 · Q1Let a,b∈Ca, b \in \mathbb{C}. Let α,β\alpha, \beta be the roots of the equation x2+ax+b=0x^2 + ax + b = 0. If β−α=11\beta - \alpha = \sqrt{11} and…MediumSingle correct
  3. 5 Apr 2026, Shift 2 · Q1Let α,β\alpha, \beta be the roots of the equation x2−x+p=0x^2-x+p=0 and γ,δ\gamma, \delta be the roots the equation x2−4x+q=0x^2-4x+q=0;…MediumSingle correct
  4. 5 Apr 2026, Shift 2 · Q2Let z1,z2∈Cz_1, z_2 \in \mathbb{C} be the distinct solutions of the equation z2+4z−(1+12i)=0z^2+4z-(1+12i)=0. Then ∣z1∣2+∣z2∣2|z_1|^2+|z_2|^2 is equal to :MediumSingle correct
  5. 6 Apr 2026, Shift 2 · Q2Consider the quadratic equation (n2−2n+2)x2−3x+(n2−2n+2)2=0(n^2-2n+2)x^2-3x+(n^2-2n+2)^2=0, n∈Rn\in\mathbf{R}. Let α\alpha be the minimum value of the product of…MediumSingle correct
  6. 3 Apr 2025, Shift 2 · Q4Let the equation x(x+2)(12−k)=2x(x + 2)(12 - k) = 2 have equal roots. Then the distance of the point (k,k2)\left(k, \frac{k}{2}\right) from the line…EasySingle correct
  7. 28 Jul 2022, Shift 1 · Q30The sum of all real values of xx for which 3x2−9x+17x2+3x+10=5x2−7x+193x2+5x+12\frac{3x^2-9x+17}{x^2+3x+10}=\frac{5x^2-7x+19}{3x^2+5x+12} is equal to __________.MediumNumerical value
  8. 6 Sep 2020, Shift 2 · Q52If α\alpha and β\beta are the roots of the equation 2x(2x+1)=12x(2x+1)=1, then β\beta is equal to :MediumSingle correct