Learn

Saturday, 31 October

JEE Main · Maths · Application of Derivatives

Intercepts of Tangent and Normal

JEE Main asked Intercepts of Tangent and Normal 3 times in 3 of the 108 shifts Lumi analysed, in 2020, 2021 and 2023. It belongs to Tangents and Normals, in Application of Derivatives (Maths). The longest wait between two years asking it was 2 years.

Updated 2026-10-24

Times asked
3
in 3 shifts
Years
3 of 8
First asked
2020
last in 2023
Pattern
Comes in cycles
across the analysed shifts

Questions on this idea a shift, by year

2017–2026. Asked in 2020, 2021 and 2023. Years differ in how many shifts Lumi analysed, so each year is scaled to one shift of 25 Maths questions.

00.050.10’170.08’200.03’210’220.07’230’240’250’26

Raw count: 2017: 0 in 1 shift · 2020: 1 in 12 shifts · 2021: 1 in 24 shifts · 2022: 0 in 24 shifts · 2023: 1 in 12 shifts · 2024: 0 in 18 shifts · 2025: 0 in 8 shifts · 2026: 0 in 9 shifts.

Shift by shift

Each square is one analysed shift, in date order. Open a filled one for that paper.

  • 20260 of 9
  • 20250 of 8
  • 20240 of 18
  • 20231 of 12
  • 20220 of 24
  • 20211 of 24
  • 20201 of 12
  • 20170 of 1

Asked in that shift More than once Not asked

How JEE Main framed it

Numerical value is the usual form. Skill tested: multi-step.

  • Intercept of normal to fitted curve
  • Point on ellipse from tangent-triangle area

Difficulty

Easy 0Medium 3Hard 0

2 of the 3 questions had a numerical answer.

Every question

All 3 questions

From the official JEE Main shift papers, newest first. Open one for the full question, the options and the official answer.

  1. 10 Apr 2023, Shift 2 · Q25Let the quadratic curve passing through the point (−1,0)(-1, 0) and touching the line y=xy = x at (1,1)(1, 1) be y=f(x)y = f(x). Then the…MediumNumerical value
  2. 4 Aug 2021, Shift 2 · Q73If the area of the triangle formed by the tangent at a point in the first quadrant on the ellipse, 4x2+3y2=124x^2+3y^2=12 and its axes is 4 sq.…MediumSingle correct
  3. 3 Sep 2020, Shift 2 · Q74If the tangent to the curve, y=exy = e^x at a point (c,ec)(c, e^c) and the normal to the parabola, y2=4xy^2 = 4x at the point (1,2)(1, 2) intersect at…MediumNumerical value

Shifts: 3 Sep 2020, Shift 2, 4 Aug 2021, Shift 2, 10 Apr 2023, Shift 2.

Same topic

Other ideas in Tangents and Normals

Tangents and Normals has 20 ideas JEE Main has asked; 7 of them came up in more than one question. The 12 most asked are below.

Topic analysisChapter analysisStudy this chapterAll repeated ideas