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Friday, 9 October

JEE Main Maths · Integrals

Generalized Reverse Product Rule

Generalized Reverse Product Rule (Integrals) was asked once in the 42 JEE Main shifts Lumi analysed, in 2023.

Times asked
1
in 1 shift
Years
2023
Usual format
Single correct
Multi-step
Pattern
Occasional
asked once so far

How it is asked

  • Integrate expression by recognising derivative

Difficulty

Easy 0Medium 0Hard 1

Where it sits

Chapter: Integrals. Topic: Integration by Parts, 6 questions over 5 ideas.

Other repeat ideas in this topic

Every time it came

The question

Newest first, each with its options and official answer.

  1. 6 Apr 2023, Shift 1 · Q11Let I(x)=∫x2(xsec⁡2x+tan⁡x)(xtan⁡x+1)2 dxI(x)=\int\frac{x^2(x\sec^2x+\tan x)}{(x\tan x+1)^2}\,dx. If I(0)=0I(0)=0, then I(π4)I\left(\frac{\pi}{4}\right) is equal toHardSingle correct