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Friday, 9 October

JEE Main Maths · Application of Derivatives

Finding Parameters from Given Extrema

Finding Parameters from Given Extrema (Application of Derivatives) was asked 3 times in 3 JEE Main shifts, 2021–2025, out of the 42 shifts Lumi analysed.

Times asked
3
in 3 shifts
Years
2021–2025
Usual format
Single correct
Multi-step
Pattern
Occasional
repeats across shifts

How it is asked

  • Find parameter from locations of local extrema
  • Find parameter from extrema relation

Difficulty

Easy 0Medium 3Hard 0

Where it sits

Chapter: Application of Derivatives. Topic: Maxima and Minima, 30 questions over 17 ideas.

Other repeat ideas in this topic

Every time it came

All 3 questions

Newest first, each with its options and official answer.

  1. 2 Apr 2025, Shift 1 · Q8If the function f(x)=2x3−9ax2+12a2x+1f(x)=2x^3-9ax^2+12a^2x+1, where a>0a>0, attains its local maximum and local minimum values at p and q, respectively, such…MediumSingle correct
  2. 4 Apr 2025, Shift 2 · Q17Let a>0a>0. If the function f(x)=6x3−45ax2+108a2x+1f(x)=6x^3-45ax^2+108a^2x+1 attains its local maximum and minimum values at the points x1x_1 and x2x_2…MediumSingle correct
  3. 3 Aug 2021, Shift 2 · Q71If the function f:R→Rf : \mathbb{R} \to \mathbb{R} defined by f(x)=x33−(2a+3b)x2+24abx+5f(x) = \frac{x^3}{3} - (2a+3b)x^2 + 24abx + 5 has a local maxima at −4-4 and…MediumSingle correct