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Friday, 9 October

JEE Main 2026 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 8 April 2026, Shift 2, Maths Q24

Question 24 of 75 in this shift, Maths question 24 of 25, Section B.

Consider the circle C:x2+y2−6x−8y−11=0C : x^2 + y^2 - 6x - 8y - 11 = 0. Let a variable chord AB of the circle C subtend a right angle at the origin. If the locus of the foot of the perpendicular drawn from the origin on the chord AB is the circle x2+y2−αx−βy−γ=0x^2 + y^2 - \alpha x - \beta y - \gamma = 0, then α+β+2γ\alpha + \beta + 2\gamma is equal to ________.

Official answer

18

NTA final key.

Chapter
Conic Sections
Topic
Pair of Straight Lines
Idea tested
Chord Subtending Right Angle via Homogenization

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.