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JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 8 April 2026, Shift 2, Maths Q19

Question 19 of 75 in this shift, Maths question 19 of 25, Section A.

Let

f(x) = \begin{cases} \frac{1}{3}, & x \le \pi/2 \\ \frac{b(1 - \sin x)}{(\pi - 2x)^2}, & x > \pi/2 \end{cases}

. If

f

is continuous at

x = \pi/2

, then the value of

\int_0^{3b-6} |x^2 + 2x - 3|\,dx

is :

(1)5
(2)2
(3)3
(4)4Official answer

Official answer

Option 4

NTA final key.

Chapter: Continuity and Differentiability
Topic: Continuity and Differentiability
Idea tested: Finding Unknowns using Continuity

Same idea in other shifts

Asked 2× in all

3 Apr 2025, Shift 1 · Q17Let $f(x) = \begin{cases} (1+ax)^{1/x}, & x < 0 \\ 1+b, & x = 0 \\ \dfrac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2}, & x > 0 \end{cases}$ be…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.