JEE Main 2026 (8 Apr, Shift 2) Maths Q16: Integrals

Question

The value of the integral $\int_0^2 \frac{\sqrt{x}\,(x^2 + x + 1)}{(\sqrt{x} + 1)\left(\sqrt{x^4 + x^2 + 1}\right)}\,dx$ is equal to :

Accepted Answer

Option 3: $\frac{2}{3}\log_e(3 + 2\sqrt{2})$

Answer

$\frac{1}{3}\log_e(3 - 2\sqrt{2})$

Answer

$\frac{2}{3}\log_e(4 + \sqrt{2})$

Answer

$\frac{2}{3}\log_e(3 + 2\sqrt{2})$

Answer

$\frac{1}{3}\log_e(1 + 6\sqrt{2})$

JEE Main 8 April 2026, Shift 2, Maths Q16