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Friday, 9 October

JEE Main 2026 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 6 April 2026, Shift 2, Chemistry Q75

Question 75 of 75 in this shift, Chemistry question 25 of 25, Section B.

Decomposition of a hydrocarbon follows the equation k=(5.5×1011 s−1) e−28000 KTk=(5.5\times10^{11}\,\mathrm{s^{-1}})\,e^{\frac{-28000\,\mathrm{K}}{T}}. The activation energy of reaction is __________ kJ mol−1^{-1}. (Nearest Integer) Given : R = 8.3 J K−1^{-1} mol−1^{-1}

Official answer

232

NTA final key.

Chapter
Chemical Kinetics
Topic
Arrhenius Equation
Idea tested
Arrhenius Exponential Form

Same idea in other shifts

Asked 2× in all
  1. 2 Apr 2017 (offline) · Q39Two reactions R1R_1 and R2R_2 have identical pre-exponential factors. Activation energy of R1R_1 exceeds that of R2R_2 by 10 kJ…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.