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Friday, 9 October

JEE Main 2026 · ChemistryMultiple choiceOtherMediumMulti-step

JEE Main 6 April 2026, Shift 2, Chemistry Q68

Question 68 of 75 in this shift, Chemistry question 18 of 25, Section A.

The number of compounds from the following which can undergo reaction with Br2\mathrm{Br_2}/KOH (alcoholic) to give respective products and these respective products can also be obtained separately by Gabriel phthalimide reaction is : [figure: six amides] H5C6−CO−NH2\mathrm{H_5C_6{-}CO{-}NH_2}; H5C6−CH2−CO−NH2\mathrm{H_5C_6{-}CH_2{-}CO{-}NH_2}; H3C−CO−NH2\mathrm{H_3C{-}CO{-}NH_2}; H11C6−CO−NHCH2CH3\mathrm{H_{11}C_6{-}CO{-}NHCH_2CH_3}; (H3C)3C−CO−NHCH3\mathrm{(H_3C)_3C{-}CO{-}NHCH_3}; H11C6−CO−NH2\mathrm{H_{11}C_6{-}CO{-}NH_2}

The figure, in words

Six amides drawn in skeletal form: benzamide (C6H5CONH2), phenylacetamide (C6H5CH2CONH2), acetamide (CH3CONH2), N-ethyl cyclohexanecarboxamide (H11C6-CO-NHCH2CH3), N-methyl pivalamide ((CH3)3C-CO-NHCH3) and cyclohexanecarboxamide (H11C6-CO-NH2).
  1. (1)5
  2. (2)4
  3. (3)3Official answer
  4. (4)6

Official answer

Option 3

NTA final key.

Chapter
Amines
Topic
Amines