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Friday, 9 October

JEE Main 2026 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 6 April 2026, Shift 2, Maths Q6

Question 6 of 75 in this shift, Maths question 6 of 25, Section A.

The sum 1+12(12+22)+13(12+22+32)+…1+\frac{1}{2}\left(1^2+2^2\right)+\frac{1}{3}\left(1^2+2^2+3^2\right)+\ldots upto 10 terms is equal to :
  1. (1)130
  2. (2)155
  3. (3)3152\frac{315}{2}Official answer
  4. (4)3252\frac{325}{2}

Official answer

Option 3

NTA final key.

Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.