JEE Main 2026 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 6 April 2026, Shift 2, Maths Q25

Question 25 of 75 in this shift, Maths question 25 of 25, Section B.

Let

f(x)=\begin{cases}x^3+8;&x<0,\\x^2-4;&x\ge0,\end{cases}

and

g(x)=\begin{cases}(x-8)^{1/3};&x<0,\\(x+4)^{1/2};&x\ge0.\end{cases}

Then the number of points, where the function

g\circ f

is discontinuous, is __________.

Official answer

NTA final key.

Chapter: Continuity and Differentiability
Topic: Continuity and Differentiability
Idea tested: Continuity and Differentiability of Composite Functions

Same idea in other shifts

Asked 3× in all

6 Apr 2024, Shift 2 · Q10Suppose for a differentiable function $h$ , $h(0)=0$ , $h(1)=1$ and $h'(0)=h'(1)=2$ . If $g(x)=h(e^x)e^{h(x)}$ , then $g'(0)$ is equal to :MediumSingle correct
16 Mar 2021, Shift 2 · Q85Let $f:\mathbf R\to\mathbf R$ and $g:\mathbf R\to\mathbf R$ be defined as $f(x)=\begin{cases}x+a, & x<0\\ |x-1|, & x\ge0\end{cases}$ and…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.