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Friday, 9 October

JEE Main 2026 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 6 April 2026, Shift 2, Maths Q22

Question 22 of 75 in this shift, Maths question 22 of 25, Section B.

If (1−x3)10=∑r=010arxr(1−x)30−2r(1-x^3)^{10}=\sum_{r=0}^{10}a_r x^r(1-x)^{30-2r}, then 9a9a10\frac{9a_9}{a_{10}} is equal to __________.

Official answer

30

NTA final key.

Topic
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Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.