JEE Main 2026 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 6 April 2026, Shift 2, Maths Q16

Question 16 of 75 in this shift, Maths question 16 of 25, Section A.

Let

\lim_{x\to2}\frac{(\tan(x-2))\left(rx^2+(p-2)x-2p\right)}{(x-2)^2}=5

for some

r, p\in\mathbf{R}

. If the set of all possible values of q, such that the roots of the equation

rx^2-px+q=0

lie in

(0,2)

, be the interval

(\alpha,\beta]

, then

4(\alpha+\beta)

equals :

(1)11
(2)13
(3)17Official answer
(4)21

Official answer

Option 3

NTA final key.

Chapter: Complex Numbers and Quadratic Equations
Topic: Location of Roots
Idea tested: Both roots in interval

Same topic in other shifts

All Location of Roots questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.