JEE Main 2026 (6 Apr, Shift 2) Maths Q11: Conic Sections

Question

The eccentricity of an ellipse E with centre at the origin O is

\frac{\sqrt{3}}{2}

and its directrices are

x=\pm\frac{4\sqrt{6}}{3}

. Let

H:\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

be a hyperbola whose eccentricity is equal to the length of semi-major axis of E, and whose length of latus rectum is equal to the length of minor axis of E. Then the distance between the foci of H is :

(1) $\frac{4\sqrt{2}}{\sqrt{7}}$
(2) $\frac{4\sqrt{2}}{7}$
(3) $\frac{4}{\sqrt{7}}$
(4) $\frac{8}{7}$ Official answer

Official answer

Option 4

NTA final key.

Accepted Answer

Option 4: $\frac{8}{7}$

Answer

$\frac{4\sqrt{2}}{\sqrt{7}}$

Answer

$\frac{4\sqrt{2}}{7}$

Answer

$\frac{4}{\sqrt{7}}$

Answer

$\frac{8}{7}$

JEE Main 6 April 2026, Shift 2, Maths Q11