JEE Main 2026 (6 Apr, Shift 1) Chemistry Q58: Consider the…

Question

Consider the following data.
Electrolyte | $\Lambda^\circ_m$ (S cm$^2$ mol$^{-1}$)
$\mathrm{BaCl_2}$ | $x_1$
$\mathrm{H_2SO_4}$ | $x_2$
$\mathrm{HCl}$ | $x_3$
$\mathrm{BaSO_4}$ is sparingly soluble in water. If the conductivity of the saturated $\mathrm{BaSO_4}$ solution is $x$ S cm$^{-1}$ then the solubility product of $\mathrm{BaSO_4}$ can be given as
(Here $\Lambda_m=\Lambda^\circ_m$)

Accepted Answer

Option 1: $\frac{10^6x^2}{\alpha^2\left(x_1+x_2-2x_3\right)^2}$

Answer

$\frac{10^6x^2}{\alpha^2\left(x_1+x_2-2x_3\right)^2}$

Answer

$\frac{x^2}{\left(x_1+x_2-2x_3\right)^2}$

Answer

$\frac{\alpha^2\left(x_1+x_2-2x_3\right)^2}{10^6x^2}$

Answer

$\frac{x^2}{\left(x_1+x_2+2x_3\right)^2}$

JEE Main 6 April 2026, Shift 1, Chemistry Q58