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Friday, 9 October

JEE Main 2026 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 6 April 2026, Shift 1, Physics Q42

Question 42 of 75 in this shift, Physics question 17 of 25, Section A.

A small cube of side 1 mm is placed at the centre of a circular loop of radius 10 cm carrying a current of 2 A. The magnetic energy stored inside the cube is α×10−14\alpha\times10^{-14} J. The value of α\alpha is ________. (μ0=4π×10−7\mu_0=4\pi\times10^{-7} Tm/A, π=3.14\pi=3.14)
  1. (1)6.28Official answer
  2. (2)6.28×10−66.28\times10^{-6}
  3. (3)628
  4. (4)6.28×10−46.28\times10^{-4}

Official answer

Option 1

NTA final key.