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Friday, 9 October

JEE Main 2026 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 6 April 2026, Shift 1, Maths Q24

Question 24 of 75 in this shift, Maths question 24 of 25, Section B.

For the functions f(θ)=αtan⁡2θ+βcot⁡2θf(\theta)=\alpha\tan^2\theta+\beta\cot^2\theta, and g(θ)=αsin⁡2θ+βcos⁡2θg(\theta)=\alpha\sin^2\theta+\beta\cos^2\theta, α>β>0\alpha>\beta>0, let min⁡0<θ<π2f(θ)=max⁡0<θ<πg(θ)\min_{0<\theta<\frac{\pi}{2}}f(\theta)=\max_{0<\theta<\pi}g(\theta). If the first term of a G.P. is (α2β)\left(\frac{\alpha}{2\beta}\right), its common ratio is (2βα)\left(\frac{2\beta}{\alpha}\right) and the sum of its first 10 terms is mn\frac{m}{n}, gcd⁡(m,n)=1\gcd(m,n)=1, then m+nm+n is equal to ________.

Official answer

1279

NTA final key.