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Friday, 9 October

JEE Main 2026 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 6 April 2026, Shift 1, Maths Q11

Question 11 of 75 in this shift, Maths question 11 of 25, Section A.

If the eccentricity ee of the hyperbola x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1, passing through (6,43)\left(6,4\sqrt{3}\right), satisfies 15(e2+1)=34e15(e^2+1)=34e, then the length of the latus rectum of the hyperbola x2b2−y22(a2+1)=1\frac{x^2}{b^2}-\frac{y^2}{2(a^2+1)}=1 is:
  1. (1)10Official answer
  2. (2)20
  3. (3)25
  4. (4)30

Official answer

Option 1

NTA final key.

Chapter
Conic Sections
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.