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Friday, 9 October

JEE Main 2026 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 5 April 2026, Shift 2, Chemistry Q74

Question 74 of 75 in this shift, Chemistry question 24 of 25, Section B.

At 298 K, the molar conductivity of x%x\% (w/w) MX solution (aqueous) is 123.5 S cm2^2 mol−1^{-1}. The conductance of same solution is 1.9×10−31.9\times10^{-3} S. The value of xx is __________ ×10−2\times10^{-2}. (Given : cell constant = 1.3 cm−1^{-1}; molar mass of MX is 75 g mol−1^{-1}, density of aqueous solution of MX at 298 K is 1.0 g mL−1^{-1})

Official answer

15

NTA final key.

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.