JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 5 April 2026, Shift 2, Physics Q44

Question 44 of 75 in this shift, Physics question 19 of 25, Section A.

Assuming the experimental mass of

{}^{12}_{6}\mathrm{C}

as 12 u, the mass defect of

{}^{12}_{6}\mathrm{C}

atom is ________

\mathrm{MeV}/c^2

. (Mass of proton = 1.00727 u, mass of neutron = 1.00866 u, 1 u = 931.5

\mathrm{MeV}/c^2

and

c

is the speed of the light in vacuum).

(1) $127.5$
(2) $89.03$ Official answer
(3) $272.0$
(4) $92.0$

Official answer

Option 2

NTA final key.

Chapter: Nuclei
Topic: Nuclear Binding Energy
Idea tested: Mass Defect Calculation

Same idea in other shifts

Asked 4× in all

8 Apr 2024, Shift 1 · Q46Binding energy of a certain nucleus is $18\times10^8$ J. How much is the difference between total mass of all the nucleons and nuclear…EasySingle correct
31 Jan 2024, Shift 1 · Q60The mass defect in a particular reaction is 0.4g. The amount of energy liberated is $n\times10^7$ kWh, where $n=$ _______. (speed of light…EasyNumerical value
3 Aug 2021, Shift 2 · Q12If $A$ , $Z$ and $M$ represents the number of nucleons, protons and mass of the nucleus respectively, then mass defect $\Delta M$ is…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.