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Friday, 9 October

JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 April 2026, Shift 2, Maths Q20

Question 20 of 75 in this shift, Maths question 20 of 25, Section A.

Let f(x)f(x) and g(x)g(x) be twice differentiable functions satisfying f′′(x)=g′′(x)f''(x)=g''(x) for all x∈Rx \in \mathbf{R}, f′(1)=2g′(1)=4f'(1)=2g'(1)=4 and g(2)=3f(2)=9g(2)=3f(2)=9. Then f(25)−g(25)f(25)-g(25) is equal to :
  1. (1)2020
  2. (2)4040Official answer
  3. (3)−20-20
  4. (4)−40-40

Official answer

Option 2

NTA final key.