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Friday, 9 October

JEE Main 2026 · MathsMultiple choiceSingle correctEasyApplication

JEE Main 5 April 2026, Shift 2, Maths Q16

Question 16 of 75 in this shift, Maths question 16 of 25, Section A.

Let O be the origin, OP→=a⃗\overrightarrow{OP}=\vec{a} and OQ→=b⃗\overrightarrow{OQ}=\vec{b}. If R is the point on OP→\overrightarrow{OP} such that OP→=5 OR→\overrightarrow{OP}=5\,\overrightarrow{OR}, and M is the point such that OQ→=5 RM→\overrightarrow{OQ}=5\,\overrightarrow{RM}, then PM→\overrightarrow{PM} is equal to :
  1. (1)15(a⃗−4b⃗)\frac{1}{5}\left(\vec{a}-4\vec{b}\right)
  2. (2)15(b⃗−4a⃗)\frac{1}{5}\left(\vec{b}-4\vec{a}\right)Official answer
  3. (3)15(−a⃗+4b⃗)\frac{1}{5}\left(-\vec{a}+4\vec{b}\right)
  4. (4)15(−b⃗+4a⃗)\frac{1}{5}\left(-\vec{b}+4\vec{a}\right)

Official answer

Option 2

NTA final key.

Topic
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Idea tested
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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.