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Friday, 9 October

JEE Main 2026 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 5 April 2026, Shift 1, Chemistry Q73

Question 73 of 75 in this shift, Chemistry question 23 of 25, Section B.

One mole of phenol is treated with dilute HNO3\mathrm{HNO_3} at 298 K to give a mixture of products. The mixture is separated by steam distillation. The steam volatile compound (X) is separated. The increase in percentage of oxygen in (X) with respect to phenol is ________ ×10−1\times 10^{-1} % (Given molar mass in g mol−1^{-1} H:1, C:12, N:14, O:16)

Official answer

175

NTA final key.