JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 5 April 2026, Shift 1, Physics Q41

Question 41 of 75 in this shift, Physics question 16 of 25, Section A.

Light source having wavelength 331 nm is used to generate photo-electrons whose stopping potential is 0.2 V. The work function of the used metal in the experiment is

\alpha \times 10^{-19}

J. The value of

\alpha

is ______. (

h = 6.62 \times 10^{-34}

J s,

e = 1.6 \times 10^{-19}

C and

c = 3 \times 10^8

m/s)

(1)3.68
(2)4.68
(3)5.68Official answer
(4)2.68

Official answer

Option 3

NTA final key.

Chapter: Dual Nature of Radiation and Matter
Topic: Photoelectric Effect
Idea tested: Einstein's Photoelectric Equation

Same idea in other shifts

Asked 4× in all

9 Apr 2024, Shift 2 · Q47UV light of $4.13$ eV is incident on a photosensitive metal surface having work function $3.13$ eV. The maximum kinetic energy of ejected…EasySingle correct
24 Jun 2022, Shift 1 · Q56When light of frequency twice the threshold frequency is incident on the metal plate, the maximum velocity of emitted electron is $v_1$ .…MediumNumerical value
8 Jan 2020, Shift 1 · Q17When photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy $T_A$ eV and…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.