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Friday, 9 October

JEE Main 2026 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 4 April 2026, Shift 1, Physics Q29

Question 29 of 75 in this shift, Physics question 4 of 25, Section A.

Two nuclei of mass number 33 combine with another nucleus of mass number 44 to yield a nucleus of mass number 1010. If the binding energy per nucleon for the mass numbers 33, 44 and 1010 are 5.65.6 MeV, 7.47.4 MeV and 6.16.1 MeV, respectively, then in the process, ΔMc2=\Delta Mc^2= ______ MeV.
  1. (1)6.96.9
  2. (2)7.97.9
  3. (3)2.22.2Official answer
  4. (4)4.34.3

Official answer

Option 3

NTA final key.

Chapter
Nuclei

Same idea in other shifts

Asked 2× in all
  1. 6 Apr 2026, Shift 2 · Q41The energy released if hydrogen atoms are combined to form 24He^{4}_{2}\mathrm{He} is __________ MeV. (Take binding energies per nucleon of…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.