If the set of all solutions of $|x^2+x-9|=|x|+|x^2-9|$ is $[\alpha,\beta]\cup[\gamma,\infty)$, then $(\alpha^2+\beta^2+\gamma^2)$ is equal to:

JEE Main 2026 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 4 April 2026, Shift 1, Maths Q2

Question 2 of 75 in this shift, Maths question 2 of 25, Section A.

If the set of all solutions of

|x^2+x-9|=|x|+|x^2-9|

[\alpha,\beta]\cup[\gamma,\infty)

, then

(\alpha^2+\beta^2+\gamma^2)

is equal to:

Official answer

Option 2

NTA final key.